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Old 09-08-2010, 09:17 AM   #1
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Default PLEASE CLOSE. Answered.

Thanks Toothache for the help
Please close.

Last edited by smvmonkey; 09-08-2010 at 12:45 PM..
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Old 09-08-2010, 09:22 AM   #2
 
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Default Re: I need help. ASAP.

Are you supposed to solve them left to right or use the Operations of Order? Either way I'll do operations of order. xD

7(3) - 2 · 4
= 21 - 8
= 13

6 ÷ 2 + 1 · 5
= 3 + 5
= 8

10 ÷ (4 + 1)
= 10 ÷ 5
= 2

3[9 · 2 ÷ (10 – 4)]
= 3 [9 · 2 ÷ 6]
= 3 [3]
= 9

I hope those are right.
Good luck! :]
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Old 09-08-2010, 09:23 AM   #3
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Default Re: I need help. ASAP.

Yes, Operations of Order Sorry, I forgot to say that. xD Thank you!
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Old 09-08-2010, 09:26 AM   #4
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Default Re: I need help. ASAP.

Sorry you're feeling sick.
Remember, parentheses first, then brackets. Multiplication and division first, then addition and subtraction.
So, the first on would be 21-8
The next one, you would do the division and mult. first...(6/2) and add (1 times 5)
Then 10 divided by (do the parentheses first) 5
The next one, start with the inside parentheses 10-4, so 6, then in the brackets do the mult. 9 times 2..then do 18/6....then multiply that by the 3.
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Old 09-08-2010, 12:29 PM   #5
it's mee
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Default Re: I need help. ASAP.

I would help you out, really. But I just got done with my algebra and really dont wanna do more, I hope i dont sound selfish.
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